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Chapters
1: Geometrical Constructions
2: Multiplication and Division of Integers
3: HCF and LCM
4: Angles and Pairs of Angles
5: Operations on Rational Numbers
6: Indices
7: Joint Bar Graph
8: Algebraic Expressions and Operations on Them
▶ *: Miscellaneous Problems : Set 1
Part Two
9: Direct Proportion and Inverse Proportion
10: Banks and Simple Interest
11: Circle
12: Perimeter and Area
13: Pythagoras’ Theorem
14: Algebraic Formulae - Expansion of Squares
15: Statistics
*: Miscellaneous Problems : Set 2
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Solutions for Chapter *: Miscellaneous Problems : Set 1
Below listed, you can find solutions for Chapter * of Maharashtra State Board Balbharati for माठेमटिक्स १ [इंग्रजी] इयत्ता ९ महाराष्ट्र राज्य मंडळ.
Balbharati solutions for माठेमटिक्स १ [इंग्रजी] इयत्ता ९ महाराष्ट्र राज्य मंडळ * Miscellaneous Problems : Set 1 Exercise [Pages 61 - 62]
Solve the following.
(−16) × (−5)
Solve the following.
(72) ÷ (−12)
Solve the following.
(−24) × (2)
Solve the following.
125 ÷ 5
Solve the following.
(−104) ÷ (−13)
Solve the following.
25 × (−4)
Find the prime factor of the following numbers and find their LCM and HCF.
75, 135
Find the prime factor of the following numbers and find their LCM and HCF.
114, 76
Find the prime factor of the following numbers and find their LCM and HCF.
153, 187
Find the prime factor of the following numbers and find their LCM and HCF.
32, 24, 48
Simplify:
`322/391`
Simplify:
`247/209`
Simplify:
`117/156`
Find the square root of the following number.
784
Find the square root of the following number.
225
Find the square root of the following number.
1296
Find the square root of the following number.
2025
Find the square root of the following number.
256
There are four polling booths for a certain election. The numbers of men and women who cast their vote at each booth is given in the table below. Draw a joint bar graph for this data.
| Polling Booths | Navodaya Vidyalaya |
Vidyaniketan School |
City High School | Eklavya School |
| Women | 500 | 520 | 680 | 800 |
| Men | 440 | 640 | 760 | 600 |
Simplify the expression.
45 ÷ 5 + 20 × 4 − 12
Simplify the expression.
(38 − 8) × 2 ÷ 5 + 13
Simplify the expression.
`5/3 + 4/7 div 32/21`
Simplify the expression.
3 × {4 [85 + 5 − (15 ÷ 3)] + 2}
Solve:
`5/12 + 7/16`
Solve:
`3 2/5 - 2 1/4`
Solve:
`12/5 xx ((-10))/3`
Solve:
`4 3/8 div 25/18`
Construct ∆ABC such that m∠A = 55°, m∠B = 60°, and l(AB) = 5.9 cm.
Construct ∆XYZ such that l(XY) = 3.7 cm, l(YZ) = 7.7 cm, l(XZ) = 6.3 cm.
Construct ∆PQR such that m∠P = 80°, m∠Q = 70°, l(QR) = 5.7 cm.
Construct ∆EFG from the given measures. l(FG) = 5 cm, m∠EFG = 90°, l(EG) = 7 cm.
In ∆LMN, l(LM) = 6.2 cm, m∠LMN = 60°, l(MN) = 4 cm. Construct ∆LMN.
Find the measures of the complementary angle of the following angle.
35°
Find the measures of the complementary angle of the following angle.
a°
Find the measure of the complementary angle of the following angle.
22°
Find the measure of the complementary angle of the following angle.
(40 - x)°
Find the measure of the supplement of the following angle.
111°
Find the measure of the supplements of the following angle.
47°
Find the measure of the supplements of the following angle.
180°
Find the measure of the supplements of the following angle.
(90 − x)°
Construct a pair of adjacent angles.
Construct the two supplementary angles which are not adjacent angles.
Construct a pair of adjacent complementary angles.

In ∆PQR, the measures of ∠P and ∠Q are equal and m∠PRQ = 70°. Find the measures of the following angles.
- m∠PRT
- m∠P
- m∠Q
Simplify:
54 × 53
Simplify:
`(2/3)^6 div (2/3)^9`
Simplify:
`(7/2)^8 xx (7/2)^-6`
Simplify:
`(4/5)^2 div (5/4)`
Find the value of 1716 ÷ 1716.
Find the value of 10−3.
Find the value of (23)2.
Find the value of 46 × 4−4.
Solve:
(6a − 5b − 8c) + (15b + 2a − 5c)
Solve:
(3x + 2y)(7x − 8y)
Solve:
(7m − 5n) − (−4n − 11m)
Solve:
(11m − 12n + 3p) − (9m + 7n − 8p)
Solve the following equation.
4(x + 12) = 8
Solve the following equation.
3y + 4 = 5y − 6
Balbharati solutions for माठेमटिक्स १ [इंग्रजी] इयत्ता ९ महाराष्ट्र राज्य मंडळ * Miscellaneous Problems : Set 1 Multiple Choice Questions [Page 62]
The three angle bisectors of a triangle are concurrent. Their point of concurrence is called the ______.
Circumcentre
Apex
Incentre
Point of intersection
`[(3/7)^-3]^4` = ______
`(3/7)^-7`
`(3/7)^-10`
`(7/3)^12`
`(3/7)^20`
The simplest form of 5 ÷ `(3/2) - 1/3` is ______.
3
5
0
`1/3`
The solution of the equation `"3x" - 1/2 = 5/2 + "x"` is ______.
`5/3`
`7/2`
4
`3/2`
Which of the following expressions has the value 37?
10 × 3 + (5 + 2)
10 × 4 + (5 - 3)
8 × 4 + 3
(9 × 3) + 2
Solutions for *: Miscellaneous Problems : Set 1
Balbharati solutions for माठेमटिक्स १ [इंग्रजी] इयत्ता ९ महाराष्ट्र राज्य मंडळ chapter * - Miscellaneous Problems : Set 1
Shaalaa.com has the Maharashtra State Board Mathematics माठेमटिक्स १ [इंग्रजी] इयत्ता ९ महाराष्ट्र राज्य मंडळ Maharashtra State Board solutions in a manner that help students grasp basic concepts better and faster. The detailed, step-by-step solutions will help you understand the concepts better and clarify any confusion. Balbharati solutions for Mathematics माठेमटिक्स १ [इंग्रजी] इयत्ता ९ महाराष्ट्र राज्य मंडळ Maharashtra State Board * (Miscellaneous Problems : Set 1) include all questions with answers and detailed explanations. This will clear students' doubts about questions and improve their application skills while preparing for board exams.
Further, we at Shaalaa.com provide such solutions so students can prepare for written exams. Balbharati textbook solutions can be a core help for self-study and provide excellent self-help guidance for students.
Concepts covered in माठेमटिक्स १ [इंग्रजी] इयत्ता ९ महाराष्ट्र राज्य मंडळ chapter * Miscellaneous Problems : Set 1 are The Property of the Angle Bisectors of a Triangle, Perpendicular Bisectors of the Sides of an Acute-angled Triangle, Construction of Triangles, Concept of Angle Bisector, Drawing a Perpendicular to a Line, Perpendicular Bisectors of the Sides of an Obtuse-angled Triangle, Constructing a Triangle When the Length of Its Three Sides Are Known (SSS Criterion), Constructing a Triangle When the Lengths of Two Sides and the Measure of the Angle Between Them Are Known. (SAS Criterion), Construct a Triangle Given Two Angles and the Included Side, Construct a Right-angled Triangle Given the Hypotenuse and One Side, Congruence Among Line Segments, Congruence of Angles, Congruence of Circles, Natural Numbers, Whole Numbers, Negative and Positive Numbers, Multiplication of Two Positive Integers, Integers, Ordering of Integers, Addition of Integers, Subtraction of Integers, Multiplication of a Positive and a Negative Integers, Multiplication of Two Negative Integers, Division of Integers, Prime Factorisation, Highest Common Factor (HCF), Lowest Common Multiple, Co-prime Numbers, Prime and Composite Numbers, Trigonometrical Ratios of Complementary Angles, Opposite Rays, Concept of Linear Pair, Supplementary Angles, Exterior Angle of a Triangle and Its Property, Concept of Pairs of Angles, Sum of Interior Angles of a Polygon, Concept of Angle, Rational Numbers, Rational Numbers Between Two Rational Numbers, Decimal Representation of Rational Numbers, Addition of Rational Number, BODMAS Rule, Multiplication of Rational Numbers, Division of Rational Numbers, Additive Inverse of Rational Number, Subtraction of Rational Number, Dividing Powers with the Same Base, Concept of Exponents, Concept of Square Number, Laws of Exponents, Multiplying Powers with the Same Base, Multiplying Powers with Different Base and Same Exponents, Finding the Square Root of a Perfect Square, Concept of Cube Number, Taking Power of a Power, Dividing Powers with Different Base and Same Exponents, Numbers with Exponent Zero, One, Negative Exponents, Miscellaneous Examples Using the Laws of Exponents, Crores, Concept of Joint Bar Graph, Interpretation of a Joint Bar Graph, Drawing a Joint Bar Graph, Addition of Algebraic Expressions, Subtraction of Algebraic Expressions, Multiplication of Algebraic Expressions, Equations in One Variable, Classification of Terms in Algebra, Multiplying Monomial by Monomials, Multiplying a Monomial by a Binomial, Multiplying a Binomial by a Binomial, Terms, Factors and Coefficients of Expression, Algebraic Expressions.
Using Balbharati माठेमटिक्स १ [इंग्रजी] इयत्ता ९ महाराष्ट्र राज्य मंडळ solutions Miscellaneous Problems : Set 1 exercise by students is an easy way to prepare for the exams, as they involve solutions arranged chapter-wise and also page-wise. The questions involved in Balbharati Solutions are essential questions that can be asked in the final exam. Maximum Maharashtra State Board माठेमटिक्स १ [इंग्रजी] इयत्ता ९ महाराष्ट्र राज्य मंडळ students prefer Balbharati Textbook Solutions to score more in exams.
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