Advertisements
Advertisements
प्रश्न
In ∆LMN, l(LM) = 6.2 cm, m∠LMN = 60°, l(MN) = 4 cm. Construct ∆LMN.
Advertisements
उत्तर
Steps of construction:
(1) Draw seg LM of length 6.2 cm.
(2) Draw ray MA such that ∠LMA = 60°.
(3) Draw an arc of 4 cm from the vertex M, cutting the ray MA at N.
Therefore, △LMN is the required triangle.
संबंधित प्रश्न
In ΔABC, l(AB) = 5.5 cm, l(BC) = 4.2 cm, l(AC) = 3.5 cm
Draw triangle with the measures given below.
In ∆FUN, l(FU) = 5 cm, l(UN) = 4.6 cm, m∠U = 110°
Draw triangle with the measures given below.
In ∆PRS, l(RS) = 5.5 cm, l(RP) = 4.2 cm, m ∠R = 90°
Construct a triangle of the measures given below.
In ∆SAT, l(AT) = 6.4 cm, m ∠A = 45°, m ∠T = 105°
Students should take examples of their own and practise the construction of triangles.
Construct an equilateral triangle using the given data: Altitude PM = 3.6 cm
Construct a triangle using the following data: PQ + PR = 10.6 cm, QR = 4.8 cm and ∠R = 45°
Construct a triangle using the given data: AB - AC = 1.2 cm, BC = 6.0 cm and ∠B = 60°
Construct a ΔXYZ with YZ = 7.5 cm, ∠Y = 60° and ∠Z = 45°. Draw the bisectors of ∠Y and ∠Z. If these bisectors meet at O, measure angle YOZ.
For constructing △XYZ where XY = 6 cm, YZ = 5 cm, and XZ = 4 cm, which construction method should be used?
