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प्रश्न
Construct a triangle of the measures given below.
In the right-angled ∆STU, hypotenuse SU = 5 cm and l(ST) = 4 cm.
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उत्तर
Steps of construction:
- Draw the Base:
- Since ST = 4 cm ST = 4 cm using a ruler.
- Construct the Right Angle at T:
- Place the protractor at point T on the line ST.
- Mark a point where the angle measures 90∘
- Draw a perpendicular line from T.
- Mark the Hypotenuse SU:
- Set your compass to measure 5 cm (the length of the hypotenuse).
- Place the compass point at S and draw an arc intersecting the perpendicular line from T.
- Label the intersection as point U.
- Complete the Triangle:
- Connect U to S and U to T.
You now have a right-angled triangle ∆STU with SU = 5 cm and ST = 4 cm.
संबंधित प्रश्न
In ∆ STU, l(ST) = 7 cm, l(TU) = 4 cm, l(SU) = 5 cm
Draw an isosceles triangle with base 5 cm and the other sides 3.5 cm each.
Construct a triangle of the measures given below.
In ∆EFG, l(EG) = 6 cm, m∠F = 65°, m∠G = 45°
Construct ∆XYZ such that l(XY) = 3.7 cm, l(YZ) = 7.7 cm, l(XZ) = 6.3 cm.
Construct a triangle using the given data: DE = 5cm, ∠D = 75° and ∠E = 60°
Construct an isosceles triangle in which: XY = XZ, YZ = 5.5 cm and ∠X = 60°
Construct an equilateral triangle using the given data: Altitude OM = 5.8 cm
Construct a triangle using the following data: DE + EF = 10.3 cm, EF = 6.4 cm and ∠E = 75°
Construct a ΔPQR with ∠Q = 60°, ∠R = 45° and the perpendicular from P to QR be 3.5 cm. Measure PQ.
Construct a ΔABC, right-angled at B with a perimeter of 10 cm and one acute angle of 60°.
