Advertisements
Advertisements
प्रश्न
Construct a triangle of the measures given below.
In the right-angled ∆STU, hypotenuse SU = 5 cm and l(ST) = 4 cm.
Advertisements
उत्तर
Steps of construction:
- Draw the Base:
- Since ST = 4 cm ST = 4 cm using a ruler.
- Construct the Right Angle at T:
- Place the protractor at point T on the line ST.
- Mark a point where the angle measures 90∘
- Draw a perpendicular line from T.
- Mark the Hypotenuse SU:
- Set your compass to measure 5 cm (the length of the hypotenuse).
- Place the compass point at S and draw an arc intersecting the perpendicular line from T.
- Label the intersection as point U.
- Complete the Triangle:
- Connect U to S and U to T.
You now have a right-angled triangle ∆STU with SU = 5 cm and ST = 4 cm.
संबंधित प्रश्न
In ΔABC, l(AB) = 5.5 cm, l(BC) = 4.2 cm, l(AC) = 3.5 cm
In ∆ PQR, l(PQ) = 6 cm, l(QR) = 3.8 cm, l(PR) = 4.5 cm
Draw an isosceles triangle with base 5 cm and the other sides 3.5 cm each.
Choose the lengths of the sides yourself and draw one equilateral, one isosceles and one scalene triangle.
Construct a triangle of the measures given below.
Construct a triangle of the measures given below.
In ∆ABC, l(AC) = 7.5 cm, m ∠ABC = 90°, l(BC) = 5.5 cm.
Construct ∆ABC such that m∠A = 55°, m∠B = 60°, and l(AB) = 5.9 cm.
In ∆LMN, l(LM) = 6.2 cm, m∠LMN = 60°, l(MN) = 4 cm. Construct ∆LMN.
Construct an equilateral triangle using the given data: Altitude PM = 3.6 cm
Construct a triangle using the given data: Perimeter of triangle is 9 cm, and the base angles are 60° and 45°
