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प्रश्न
Construct a triangle of the measures given below.
In the right-angled ∆STU, hypotenuse SU = 5 cm and l(ST) = 4 cm.
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उत्तर
Steps of construction:
- Draw the Base:
- Since ST = 4 cm ST = 4 cm using a ruler.
- Construct the Right Angle at T:
- Place the protractor at point T on the line ST.
- Mark a point where the angle measures 90∘
- Draw a perpendicular line from T.
- Mark the Hypotenuse SU:
- Set your compass to measure 5 cm (the length of the hypotenuse).
- Place the compass point at S and draw an arc intersecting the perpendicular line from T.
- Label the intersection as point U.
- Complete the Triangle:
- Connect U to S and U to T.
You now have a right-angled triangle ∆STU with SU = 5 cm and ST = 4 cm.

संबंधित प्रश्न
The perimeter of a triangle is 14.4 cm and the ratio of lengths of its side is 2 : 3 : 4. Construct the triangle.
Draw an isosceles triangle with base 5 cm and the other sides 3.5 cm each.
Draw triangle with the measures given below.
In ∆MAT, l(MA) = 5.2 cm, m∠A = 80°, l(AT) = 6 cm
Draw triangle with the measures given below.
In ∆ NTS, m ∠T = 40°, l(NT) = l(TS) = 5 cm
Construct a triangle of the measures given below.
In ∆MNP, l(NP) = 5.2 cm, m∠N = 70°, m ∠P = 40°
Construct a triangle using the given data: BC = 6cm, AC = 5.0cm and ∠C = 60°
Construct a triangle using the given data: XY = 5.2cm, XZ = 6.5cm and ∠X = 75°
Construct a right-angled triangle in which: QP = QR and hypotenuse PR = 7 cm
Construct an isosceles triangle in which: AB = AC, BC = 6 cm and ∠B = 75°
Construct a ΔRST with side ST = 5.4 cm, RST = 60° and the perpendicular from R on ST = 3.0 cm.
