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प्रश्न
Construct a triangle of the measures given below.
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उत्तर
Steps of construction:
- Draw a line AN = 8 cm.
- With A as a centre, draw ∠XAN = 90º.
- With N as the centre and 10 cm as radius, cut an arc on XA and name it as point M.
- Join MN.
∆MAN is thus formed.
संबंधित प्रश्न
In ∆ STU, l(ST) = 7 cm, l(TU) = 4 cm, l(SU) = 5 cm
In ∆ PQR, l(PQ) = 6 cm, l(QR) = 3.8 cm, l(PR) = 4.5 cm
Draw an isosceles triangle with base 5 cm and the other sides 3.5 cm each.
Choose the lengths of the sides yourself and draw one equilateral, one isosceles and one scalene triangle.
Construct a triangle of the measures given below.
In ∆MNP, l(NP) = 5.2 cm, m∠N = 70°, m ∠P = 40°
Construct a triangle of the measures given below.
Construct a triangle of the measures given below.
In the right-angled ∆STU, hypotenuse SU = 5 cm and l(ST) = 4 cm.
Construct a triangle using the given data: XY = 5.2cm, XZ = 6.5cm and ∠X = 75°
Construct a triangle using the given data: BC = 6.0cm, ∠B = 60° and ∠C = 45°
Construct a ΔPQR with ∠Q = 60°, ∠R = 45° and the perpendicular from P to QR be 3.5 cm. Measure PQ.
