Advertisements
Advertisements
प्रश्न
Construct a triangle of the measures given below.
Advertisements
उत्तर
Steps of construction:
- Draw a line AN = 8 cm.
- With A as a centre, draw ∠XAN = 90º.
- With N as the centre and 10 cm as radius, cut an arc on XA and name it as point M.
- Join MN.
∆MAN is thus formed.

संबंधित प्रश्न
In ∆ PQR, l(PQ) = 6 cm, l(QR) = 3.8 cm, l(PR) = 4.5 cm
Choose the lengths of the sides yourself and draw one equilateral, one isosceles and one scalene triangle.
Draw triangle with the measures given below.
In ∆ NTS, m ∠T = 40°, l(NT) = l(TS) = 5 cm
Construct a triangle of the measures given below.
In ∆ABC, l(AC) = 7.5 cm, m ∠ABC = 90°, l(BC) = 5.5 cm.
Construct a triangle using the given data: BC = 6cm, AC = 5.0cm and ∠C = 60°
Construct a triangle using the given data: PQ = 6.2cm, QR = 9.0cm and ∠Q = 30°
Construct a triangle using the given data: BC = 6.0cm, ∠B = 60° and ∠C = 45°
Construct a right-angled triangle in which: QP = QR and hypotenuse PR = 7 cm
Construct a triangle using the given data: Perimeter of triangle is 10.6 cm, and the base angles are 60° and 45°
Construct a ΔPQR with ∠Q = 60°, ∠R = 45° and the perpendicular from P to QR be 3.5 cm. Measure PQ.
