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प्रश्न
In ∆ STU, l(ST) = 7 cm, l(TU) = 4 cm, l(SU) = 5 cm
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उत्तर
Steps of construction:
- Draw a line ST = 7 cm.
- With S as centre and 5 cm as the radius, draw an arc above the line ST.
- With T as the center and 4 cm as the radius, draw an arc cutting the previous drawn arc at point U.
- Join US and UT.
संबंधित प्रश्न
In ΔABC, l(AB) = 5.5 cm, l(BC) = 4.2 cm, l(AC) = 3.5 cm
Draw an equilateral triangle with side 6.5 cm.
Choose the lengths of the sides yourself and draw one equilateral, one isosceles and one scalene triangle.
Draw triangle with the measures given below.
In ∆ NTS, m ∠T = 40°, l(NT) = l(TS) = 5 cm
Construct a triangle of the measures given below.
In ∆ABC, l(AC) = 7.5 cm, m ∠ABC = 90°, l(BC) = 5.5 cm.
Students should take examples of their own and practise the construction of triangles.
Construct a right-angled triangle in which: QP = QR and hypotenuse PR = 7 cm
Construct a triangle using the given data: AB - AC = 1.2 cm, BC = 6.0 cm and ∠B = 60°
Construct a triangle using the given data: Perimeter of triangle is 10.6 cm, and the base angles are 60° and 45°
Construct a ΔPQR with ∠Q = 60°, ∠R = 45° and the perpendicular from P to QR be 3.5 cm. Measure PQ.
