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प्रश्न
Construct a triangle of the measures given below.
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उत्तर
Steps of construction:
- Draw the Base:
- Draw PQ = 4.5 cm using a ruler.
- Construct the Right Angle at Q:
- Place the protractor at point Q on PQ.
- Mark a 90∘ angle and draw a perpendicular line from Q.
- Locate Point R:
- Set your compass to measure PR = 11.7 cm.
- Place the compass point at P and draw an arc that intersects the perpendicular line from Q.
- Label the intersection as point R.
- Complete the Triangle:
- Connect R to P and R to Q.
You now have ∆PQR with PQ = 4.5 cm, PR = 11.7 cm, and ∠PQR = 90∘.

संबंधित प्रश्न
In ∆ STU, l(ST) = 7 cm, l(TU) = 4 cm, l(SU) = 5 cm
In ∆ PQR, l(PQ) = 6 cm, l(QR) = 3.8 cm, l(PR) = 4.5 cm
Draw an isosceles triangle with base 5 cm and the other sides 3.5 cm each.
Construct a triangle of the measures given below.
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In ∆LMN, l(LM) = 6.2 cm, m∠LMN = 60°, l(MN) = 4 cm. Construct ∆LMN.
Construct a triangle using the given data: AB = 6.5cm, BC = 8.4cm and AC = 7.2cm
Construct a right-angled triangle in which: QP = QR and hypotenuse PR = 7 cm
Construct a triangle using the given data: PQ - PR = 1.5 cm, QR = 6.0 and ∠Q = 45°
Construct a ΔPQR with ∠Q = 60°, ∠R = 45° and the perpendicular from P to QR be 3.5 cm. Measure PQ.
