Advertisements
Advertisements
प्रश्न
Construct ∆EFG from the given measures. l(FG) = 5 cm, m∠EFG = 90°, l(EG) = 7 cm.
Advertisements
उत्तर
Steps of construction:
(1) Draw seg FG of length 5 cm.
(2) Draw ray FA such that ∠GFA = 90°.
(3) Draw an arc of 7 cm from the vertex G, cutting the ray FA at E.
Therefore, △DEF is the required triangle.
संबंधित प्रश्न
The perimeter of a triangle is 14.4 cm and the ratio of lengths of its side is 2 : 3 : 4. Construct the triangle.
Construct a triangle of the measures given below.
In ∆EFG, l(EG) = 6 cm, m∠F = 65°, m∠G = 45°
Construct a triangle of the measures given below.
Construct ∆ABC such that m∠A = 55°, m∠B = 60°, and l(AB) = 5.9 cm.
Construct ∆PQR such that m∠P = 80°, m∠Q = 70°, l(QR) = 5.7 cm.
Construct a triangle using the given data: XY = 5.2cm, XZ = 6.5cm and ∠X = 75°
Construct an isosceles triangle in which: PQ = QR, PR = 4.5 cm and ∠R = 60°
Construct an equilateral triangle using the given data: Altitude PM = 3.6 cm
Construct a triangle using the given data: PQ - PR = 1.5 cm, QR = 6.0 and ∠Q = 45°
Construct a ΔABC, right-angled at B with a perimeter of 10 cm and one acute angle of 60°.
