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प्रश्न
Draw an equilateral triangle with side 6.5 cm.
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उत्तर
Steps of construction:
- Draw a line BC = 6.5 cm.
- With B as a centre and 6.5 cm as radius, draw an arc above the line BC.
- With C as a centre and 6.5 cm as radius, draw an arc cutting the previous drawn arc. Name the point of intersection as point A.
- Join AB and AC.
△ABC is the required equilateral triangle.
संबंधित प्रश्न
In ∆ PQR, l(PQ) = 6 cm, l(QR) = 3.8 cm, l(PR) = 4.5 cm
Draw triangle with the measures given below.
In ∆ NTS, m ∠T = 40°, l(NT) = l(TS) = 5 cm
Construct ∆PQR such that m∠P = 80°, m∠Q = 70°, l(QR) = 5.7 cm.
Construct ∆EFG from the given measures. l(FG) = 5 cm, m∠EFG = 90°, l(EG) = 7 cm.
Construct a triangle using the given data: PQ = 4.8cm, QR = 6.3cm and PR = 5.5cm
Construct a triangle using the given data: DE = 6.5cm, EF = 5.8cm and DF = 4.2cm
Construct a triangle using the given data: PQ = 6.2cm, QR = 9.0cm and ∠Q = 30°
Construct a triangle using the given data: BC = 6.0cm, ∠B = 60° and ∠C = 45°
Construct a triangle using the following data: XY + YZ = 5.6 cm, XZ = 4.5 cm and ∠X = 45°
Construct a ΔRST with side ST = 5.4 cm, RST = 60° and the perpendicular from R on ST = 3.0 cm.
