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प्रश्न
Draw triangle with the measures given below.
In ∆ NTS, m ∠T = 40°, l(NT) = l(TS) = 5 cm
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उत्तर
Steps of construction:
- Draw a line TS = 5 cm.
- With T as a centre, draw an angle of 40°° using protractor. Name this angle as ∠∠XTS.
- With T as a centre and 5 cm as radius, cut an arc on XT and name it as point N.
- Join NS.
∆NTS is the required triangle.
संबंधित प्रश्न
In ΔABC, l(AB) = 5.5 cm, l(BC) = 4.2 cm, l(AC) = 3.5 cm
In ∆ PQR, l(PQ) = 6 cm, l(QR) = 3.8 cm, l(PR) = 4.5 cm
Draw an isosceles triangle with base 5 cm and the other sides 3.5 cm each.
Construct a triangle of the measures given below.
Construct a triangle using the given data: XY = 5.2cm, XZ = 6.5cm and ∠X = 75°
Construct a right-angled triangle in which: Side AB = 4.5 cm and hypotenuse AC = 7 cm
Construct a right-angled triangle in which: QP = QR and hypotenuse PR = 7 cm
Construct an equilateral triangle using the given data: Altitude PM = 3.6 cm
Construct a triangle using the given data: Perimeter of triangle is 6.4 cm, and the base angles are 60° and 45°
For Construction of △ABC where AB = 4 cm, ∠A = 60°, and ∠B = 30°, what is the critical step used to locate vertex C?
