Advertisements
Advertisements
प्रश्न
Draw triangle with the measures given below.
In ∆ NTS, m ∠T = 40°, l(NT) = l(TS) = 5 cm
Advertisements
उत्तर
Steps of construction:
- Draw a line TS = 5 cm.
- With T as a centre, draw an angle of 40°° using protractor. Name this angle as ∠∠XTS.
- With T as a centre and 5 cm as radius, cut an arc on XT and name it as point N.
- Join NS.
∆NTS is the required triangle.
संबंधित प्रश्न
The perimeter of a triangle is 14.4 cm and the ratio of lengths of its side is 2 : 3 : 4. Construct the triangle.
In ∆LMN, l(LM) = 6.2 cm, m∠LMN = 60°, l(MN) = 4 cm. Construct ∆LMN.
Construct an isosceles triangle in which: AB = AC, BC = 6 cm and ∠B = 75°
Construct an equilateral triangle using the given data: Altitude AD = 5 cm
Construct a triangle using the following data: XY + YZ = 5.6 cm, XZ = 4.5 cm and ∠X = 45°
Construct a triangle using the given data: PQ - PR = 1.5 cm, QR = 6.0 and ∠Q = 45°
Construct a triangle PQR with PQ = 5.4 cm, QR = 4.6 cm and ∠Q = 60°. Draw the perpendicular PS at QR, measure the lengths of SP and SQ,
Construct a ΔPQR with ∠Q = 60°, ∠R = 45° and the perpendicular from P to QR be 3.5 cm. Measure PQ.
Which tool is essential for drawing arcs while constructing a triangle using given side measurements?
For constructing △XYZ where XY = 6 cm, YZ = 5 cm, and XZ = 4 cm, which construction method should be used?
