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प्रश्न
Draw triangle with the measures given below.
In ∆ NTS, m ∠T = 40°, l(NT) = l(TS) = 5 cm
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उत्तर
Steps of construction:
- Draw a line TS = 5 cm.
- With T as a centre, draw an angle of 40°° using protractor. Name this angle as ∠∠XTS.
- With T as a centre and 5 cm as radius, cut an arc on XT and name it as point N.
- Join NS.
∆NTS is the required triangle.
संबंधित प्रश्न
In ∆ PQR, l(PQ) = 6 cm, l(QR) = 3.8 cm, l(PR) = 4.5 cm
Construct a triangle of the measures given below.
In ∆EFG, l(EG) = 6 cm, m∠F = 65°, m∠G = 45°
Students should take examples of their own and practise the construction of triangles.
Construct ∆PQR such that m∠P = 80°, m∠Q = 70°, l(QR) = 5.7 cm.
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Construct a triangle using the given data: AB - AC = 1.2 cm, BC = 6.0 cm and ∠B = 60°
