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प्रश्न
Students should take examples of their own and practise the construction of triangles.
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उत्तर
In ∆PQR, l(PR) = 8 cm, m ∠PQR = 90° , l(QR) = 6 cm.
Steps of construction:
- Draw a line QR = 6 cm.
- With Q as centre, draw ∠XQR = 90º.
- With R as centre and 8 cm as radius, cut an arc on XQ and name it as point P.
- Join PR.
∆PQR is thus formed.
संबंधित प्रश्न
In ∆ STU, l(ST) = 7 cm, l(TU) = 4 cm, l(SU) = 5 cm
Draw an isosceles triangle with base 5 cm and the other sides 3.5 cm each.
Draw triangle with the measures given below.
In ∆ NTS, m ∠T = 40°, l(NT) = l(TS) = 5 cm
Construct a triangle of the measures given below.
In ∆SAT, l(AT) = 6.4 cm, m ∠A = 45°, m ∠T = 105°
Construct a triangle of the measures given below.
Construct a triangle using the given data: DE = 6.5cm, EF = 5.8cm and DF = 4.2cm
Construct a triangle using the given data: XY = 5.2cm, XZ = 6.5cm and ∠X = 75°
Construct an isosceles triangle in which: AB = AC, BC = 6 cm and ∠B = 75°
Construct a ΔPQR with ∠Q = 60°, ∠R = 45° and the perpendicular from P to QR be 3.5 cm. Measure PQ.
Select the correct sequence for constructing a triangle given the three sides:
