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प्रश्न
Students should take examples of their own and practise the construction of triangles.
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उत्तर
In ∆PQR, l(PR) = 8 cm, m ∠PQR = 90° , l(QR) = 6 cm.
Steps of construction:
- Draw a line QR = 6 cm.
- With Q as centre, draw ∠XQR = 90º.
- With R as centre and 8 cm as radius, cut an arc on XQ and name it as point P.
- Join PR.
∆PQR is thus formed.

संबंधित प्रश्न
In ∆ PQR, l(PQ) = 6 cm, l(QR) = 3.8 cm, l(PR) = 4.5 cm
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In ∆EFG, l(EG) = 6 cm, m∠F = 65°, m∠G = 45°
Construct a triangle of the measures given below.
In ∆ABC, l(AC) = 7.5 cm, m ∠ABC = 90°, l(BC) = 5.5 cm.
Construct a triangle using the given data: PQ = 4.8cm, QR = 6.3cm and PR = 5.5cm
Construct a triangle using the given data: BC = 6cm, AC = 5.0cm and ∠C = 60°
Construct an isosceles triangle in which: AB = AC, BC = 6 cm and ∠B = 75°
Construct a triangle using the following data: DE + EF = 10.3 cm, EF = 6.4 cm and ∠E = 75°
Construct a triangle using the given data: Perimeter of triangle is 9 cm, and the base angles are 60° and 45°
Construct a triangle using the given data: Perimeter of triangle is 10.6 cm, and the base angles are 60° and 45°
For constructing △XYZ where XY = 6 cm, YZ = 5 cm, and XZ = 4 cm, which construction method should be used?
