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Question
Students should take examples of their own and practise the construction of triangles.
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Solution
In ∆PQR, l(PR) = 8 cm, m ∠PQR = 90° , l(QR) = 6 cm.
Steps of construction:
- Draw a line QR = 6 cm.
- With Q as centre, draw ∠XQR = 90º.
- With R as centre and 8 cm as radius, cut an arc on XQ and name it as point P.
- Join PR.
∆PQR is thus formed.
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