Advertisements
Advertisements
Question
Students should take examples of their own and practise the construction of triangles.
Advertisements
Solution
In ∆PQR, l(PR) = 8 cm, m ∠PQR = 90° , l(QR) = 6 cm.
Steps of construction:
- Draw a line QR = 6 cm.
- With Q as centre, draw ∠XQR = 90º.
- With R as centre and 8 cm as radius, cut an arc on XQ and name it as point P.
- Join PR.
∆PQR is thus formed.
RELATED QUESTIONS
Draw triangle with the measures given below.
In ∆PRS, l(RS) = 5.5 cm, l(RP) = 4.2 cm, m ∠R = 90°
Construct a triangle of the measures given below.
In ∆EFG, l(EG) = 6 cm, m∠F = 65°, m∠G = 45°
Construct a triangle of the measures given below.
In the right-angled ∆STU, hypotenuse SU = 5 cm and l(ST) = 4 cm.
Construct a triangle using the given data: PQ = 4.8cm, QR = 6.3cm and PR = 5.5cm
Construct a triangle using the given data: XY = 5.2cm, XZ = 6.5cm and ∠X = 75°
Construct a triangle using the given data: PQ = 6.2cm, QR = 9.0cm and ∠Q = 30°
Construct a right-angled triangle in which: Side AB = 4.5 cm and hypotenuse AC = 7 cm
Construct a right-angled triangle in which Side DE = 6 cm and ∠E = 30°, ∠D = 90°
Construct an isosceles triangle in which: AB = AC, BC = 6 cm and ∠B = 75°
Construct a triangle using the following data: DE + EF = 10.3 cm, EF = 6.4 cm and ∠E = 75°
