Advertisements
Advertisements
प्रश्न
Draw an equilateral triangle with side 6.5 cm.
Advertisements
उत्तर
Steps of construction:
- Draw a line BC = 6.5 cm.
- With B as a centre and 6.5 cm as radius, draw an arc above the line BC.
- With C as a centre and 6.5 cm as radius, draw an arc cutting the previous drawn arc. Name the point of intersection as point A.
- Join AB and AC.
△ABC is the required equilateral triangle.

संबंधित प्रश्न
The perimeter of a triangle is 14.4 cm and the ratio of lengths of its side is 2 : 3 : 4. Construct the triangle.
Construct a triangle of the measures given below.
In ∆MNP, l(NP) = 5.2 cm, m∠N = 70°, m ∠P = 40°
Construct ∆XYZ such that l(XY) = 3.7 cm, l(YZ) = 7.7 cm, l(XZ) = 6.3 cm.
In ∆LMN, l(LM) = 6.2 cm, m∠LMN = 60°, l(MN) = 4 cm. Construct ∆LMN.
Construct a right-angled triangle in which Side DE = 6 cm and ∠E = 30°, ∠D = 90°
Construct an equilateral triangle using the given data: Altitude AD = 5 cm
Construct a ΔXYZ with YZ = 7.5 cm, ∠Y = 60° and ∠Z = 45°. Draw the bisectors of ∠Y and ∠Z. If these bisectors meet at O, measure angle YOZ.
Construct a triangle PQR with PQ = 5.4 cm, QR = 4.6 cm and ∠Q = 60°. Draw the perpendicular PS at QR, measure the lengths of SP and SQ,
Which tool is essential for drawing arcs while constructing a triangle using given side measurements?
For constructing △XYZ where XY = 6 cm, YZ = 5 cm, and XZ = 4 cm, which construction method should be used?
