Advertisements
Advertisements
प्रश्न
Construct a ΔABC, right-angled at B with a perimeter of 10 cm and one acute angle of 60°.
Advertisements
उत्तर
Steps of construction:
1. Draw DE = 10 cm.
2. Draw DP and EQ such that ∠PDE = 90° and ∠QED = 60°.
3. Draw AD and AE, the bisectors of angles PDE and QED respectively, intersecting each other at A.
4. Draw perpendicular bisector of AD and AE, interesting DE at points B and C respectively.
5. Join AB and AC.
Thus, ABC is the required triangle.
APPEARS IN
संबंधित प्रश्न
In ∆ PQR, l(PQ) = 6 cm, l(QR) = 3.8 cm, l(PR) = 4.5 cm
Draw an equilateral triangle with side 6.5 cm.
Draw triangle with the measures given below.
In ∆MAT, l(MA) = 5.2 cm, m∠A = 80°, l(AT) = 6 cm
Construct a triangle of the measures given below.
Construct a triangle using the given data: BC = 6cm, AC = 5.0cm and ∠C = 60°
Construct an equilateral triangle using the given data: Altitude AD = 5 cm
Construct an equilateral triangle using the given data: Altitude PM = 3.6 cm
Construct an equilateral triangle using the given data: Altitude OM = 5.8 cm
Construct a triangle using the given data: AB - AC = 1.2 cm, BC = 6.0 cm and ∠B = 60°
In Construction of triangle ABC where AB = 3 cm, BC = 5 cm, and ∠ABC = 60°, which side must be drawn first as the base?
