Advertisements
Advertisements
प्रश्न
Construct a triangle of the measures given below.
In ∆SAT, l(AT) = 6.4 cm, m ∠A = 45°, m ∠T = 105°
Advertisements
उत्तर
Steps of construction:
- Draw a line AT = 6.4 cm.
- With A as a centre, draw ∠SAT = 45°.
- With T as a centre, draw ∠STA = 105º.
- Let ST and SA meet at point S.
∆SAT is the required triangle.
संबंधित प्रश्न
The perimeter of a triangle is 14.4 cm and the ratio of lengths of its side is 2 : 3 : 4. Construct the triangle.
Draw an isosceles triangle with base 5 cm and the other sides 3.5 cm each.
Choose the lengths of the sides yourself and draw one equilateral, one isosceles and one scalene triangle.
Construct ∆ABC such that m∠A = 55°, m∠B = 60°, and l(AB) = 5.9 cm.
Construct a triangle using the given data: BC = 6.0cm, ∠B = 60° and ∠C = 45°
Construct a triangle using the given data: PQ = 6.2cm, ∠P = 105° and ∠ = 45°
Construct an isosceles triangle in which: AB = AC, BC = 6 cm and ∠B = 75°
Construct a triangle using the following data: XY + YZ = 5.6 cm, XZ = 4.5 cm and ∠X = 45°
Construct a triangle using the following data: DE + EF = 10.3 cm, EF = 6.4 cm and ∠E = 75°
Construct a triangle using the given data: AB - AC = 1.2 cm, BC = 6.0 cm and ∠B = 60°
