Advertisements
Advertisements
प्रश्न
Construct a right-angled triangle in which: QP = QR and hypotenuse PR = 7 cm
Advertisements
उत्तर
In ΔPQR,
QP = QR ....(given)
⇒ ∠QPR = ∠QRP ....
Since hypotenuse PR = 7cm, ∠PQR = 90°
∴ ∠QPR + ∠QRP = 90°
⇒ ∠QPR = ∠QRP = 45°
Steps:
1. Draw PR = 7cm.
2. Draw a ray PT such as ∠RPT = 45° and ray RS such as ∠PRS = 45°
3. Ray RS and ray PT meets at Q.
Thus, PQR is the required triangle.
APPEARS IN
संबंधित प्रश्न
Draw an isosceles triangle with base 5 cm and the other sides 3.5 cm each.
Construct a triangle of the measures given below.
In the right-angled ∆STU, hypotenuse SU = 5 cm and l(ST) = 4 cm.
Construct a triangle using the given data: BC = 6cm, AC = 5.0cm and ∠C = 60°
Construct a right-angled triangle in which Side DE = 6 cm and ∠E = 30°, ∠D = 90°
Construct an isosceles triangle in which: XY = XZ, YZ = 5.5 cm and ∠X = 60°
Construct an equilateral triangle using the given data: Altitude PM = 3.6 cm
Construct a triangle using the given data: PQ - PR = 1.5 cm, QR = 6.0 and ∠Q = 45°
Construct a triangle using the given data: AB - AC = 1.2 cm, BC = 6.0 cm and ∠B = 60°
For constructing △XYZ where XY = 6 cm, YZ = 5 cm, and XZ = 4 cm, which construction method should be used?
In Construction of triangle ABC where AB = 3 cm, BC = 5 cm, and ∠ABC = 60°, which side must be drawn first as the base?
