Advertisements
Advertisements
प्रश्न
Construct an isosceles triangle in which: AB = AC, BC = 6 cm and ∠B = 75°
Advertisements
उत्तर
In ΔABC,
AB = AC ....(given)
⇒ ∠ACB = ∠ABC = 75°
Steps:
1. Draw BC = 6cm.
2. Construct angle ∠BCM = 75° and ∠CBN = 75°
3. Ray CM and ray BN meets at A.
Thus, ABC is required angle.
APPEARS IN
संबंधित प्रश्न
In ∆ PQR, l(PQ) = 6 cm, l(QR) = 3.8 cm, l(PR) = 4.5 cm
Draw an isosceles triangle with base 5 cm and the other sides 3.5 cm each.
Draw an equilateral triangle with side 6.5 cm.
Construct a triangle of the measures given below.
In the right-angled ∆STU, hypotenuse SU = 5 cm and l(ST) = 4 cm.
Construct a right-angled triangle in which Side DE = 6 cm and ∠E = 30°, ∠D = 90°
Construct an equilateral triangle using the given data: Altitude OM = 5.8 cm
Construct a triangle using the following data: DE + EF = 10.3 cm, EF = 6.4 cm and ∠E = 75°
For constructing △XYZ where XY = 6 cm, YZ = 5 cm, and XZ = 4 cm, which construction method should be used?
In Construction of triangle ABC where AB = 3 cm, BC = 5 cm, and ∠ABC = 60°, which side must be drawn first as the base?
In Construction of △ABC where AB = 3 cm, BC = 5 cm, and ∠ABC = 60°, which side must be drawn first as the base?
