Advertisements
Advertisements
Question
Construct a right-angled triangle in which: QP = QR and hypotenuse PR = 7 cm
Advertisements
Solution
In ΔPQR,
QP = QR ....(given)
⇒ ∠QPR = ∠QRP ....
Since hypotenuse PR = 7cm, ∠PQR = 90°
∴ ∠QPR + ∠QRP = 90°
⇒ ∠QPR = ∠QRP = 45°
Steps:
1. Draw PR = 7cm.
2. Draw a ray PT such as ∠RPT = 45° and ray RS such as ∠PRS = 45°
3. Ray RS and ray PT meets at Q.
Thus, PQR is the required triangle.
APPEARS IN
RELATED QUESTIONS
Choose the lengths of the sides yourself and draw one equilateral, one isosceles and one scalene triangle.
Draw triangle with the measures given below.
In ∆ NTS, m ∠T = 40°, l(NT) = l(TS) = 5 cm
Draw triangle with the measures given below.
In ∆PRS, l(RS) = 5.5 cm, l(RP) = 4.2 cm, m ∠R = 90°
Students should take examples of their own and practise the construction of triangles.
Construct ∆EFG from the given measures. l(FG) = 5 cm, m∠EFG = 90°, l(EG) = 7 cm.
Construct a right-angled triangle in which Side DE = 6 cm and ∠E = 30°, ∠D = 90°
Construct an isosceles triangle in which: PQ = QR, PR = 4.5 cm and ∠R = 60°
Construct a triangle using the given data: AB - AC = 1.2 cm, BC = 6.0 cm and ∠B = 60°
Construct a ΔRST with side ST = 5.4 cm, RST = 60° and the perpendicular from R on ST = 3.0 cm.
Which tool is essential for drawing arcs while constructing a triangle using given side measurements?
