Advertisements
Advertisements
प्रश्न
Construct a triangle of the measures given below.
In ∆ABC, l(AC) = 7.5 cm, m ∠ABC = 90°, l(BC) = 5.5 cm.
Advertisements
उत्तर
Steps of construction:
- Draw a line BC = 5.5 cm.
- With B as a centre, draw ∠XBC = 90º.
- With C as a centre and 7.5 cm as radius, cut an arc on XB and name it as point A.
- Join AC.
∆ABC is thus formed.
संबंधित प्रश्न
In ΔABC, l(AB) = 5.5 cm, l(BC) = 4.2 cm, l(AC) = 3.5 cm
In ∆ PQR, l(PQ) = 6 cm, l(QR) = 3.8 cm, l(PR) = 4.5 cm
Construct a triangle of the measures given below.
In ∆SAT, l(AT) = 6.4 cm, m ∠A = 45°, m ∠T = 105°
Construct a triangle of the measures given below.
In ∆EFG, l(EG) = 6 cm, m∠F = 65°, m∠G = 45°
Construct a triangle of the measures given below.
Construct ∆PQR such that m∠P = 80°, m∠Q = 70°, l(QR) = 5.7 cm.
Construct a triangle using the given data: DE = 6.5cm, EF = 5.8cm and DF = 4.2cm
Construct a triangle using the given data: XY = 5.2cm, XZ = 6.5cm and ∠X = 75°
Construct a triangle using the given data: BC = 6.0cm, ∠B = 60° and ∠C = 45°
Construct an isosceles triangle in which: AB = AC, BC = 6 cm and ∠B = 75°
