Advertisements
Advertisements
Question
In ∆LMN, l(LM) = 6.2 cm, m∠LMN = 60°, l(MN) = 4 cm. Construct ∆LMN.
Advertisements
Solution

Steps of construction:
(1) Draw seg LM of length 6.2 cm.
(2) Draw ray MA such that ∠LMA = 60°.
(3) Draw an arc of 4 cm from the vertex M, cutting the ray MA at N.
Therefore, △LMN is the required triangle.
RELATED QUESTIONS
In ∆ STU, l(ST) = 7 cm, l(TU) = 4 cm, l(SU) = 5 cm
Draw triangle with the measures given below.
In ∆FUN, l(FU) = 5 cm, l(UN) = 4.6 cm, m∠U = 110°
Construct a triangle of the measures given below.
In ∆MNP, l(NP) = 5.2 cm, m∠N = 70°, m ∠P = 40°
Construct a triangle of the measures given below.
Construct a triangle of the measures given below.
In the right-angled ∆STU, hypotenuse SU = 5 cm and l(ST) = 4 cm.
Construct a right-angled triangle in which Side DE = 6 cm and ∠E = 30°, ∠D = 90°
Construct an isosceles triangle in which: AB = AC, BC = 6 cm and ∠B = 75°
Construct a triangle using the following data: PQ + PR = 10.6 cm, QR = 4.8 cm and ∠R = 45°
Construct a triangle using the given data: AB - AC = 1.2 cm, BC = 6.0 cm and ∠B = 60°
Construct a ΔRST with side ST = 5.4 cm, RST = 60° and the perpendicular from R on ST = 3.0 cm.
