Advertisements
Advertisements
Question
In ΔABC, l(AB) = 5.5 cm, l(BC) = 4.2 cm, l(AC) = 3.5 cm
Advertisements
Solution
Steps of construction:
- Draw a line AB = 5.5 cm.
- With A as a centre and 3.5 cm as the radius, draw an arc above the line AB.
- With B as the center and 4.2 cm as the radius, draw an arc cutting the previous drawn arc at point C.
- Join CA and CB.
Δ ABC is thus the required triangle.

RELATED QUESTIONS
Draw triangle with the measures given below.
In ∆MAT, l(MA) = 5.2 cm, m∠A = 80°, l(AT) = 6 cm
Construct a triangle of the measures given below.
In ∆SAT, l(AT) = 6.4 cm, m ∠A = 45°, m ∠T = 105°
Construct a triangle of the measures given below.
In ∆EFG, l(EG) = 6 cm, m∠F = 65°, m∠G = 45°
Construct a triangle using the given data: BC = 6cm, AC = 5.0cm and ∠C = 60°
Construct a triangle using the given data: XY = 5.2cm, XZ = 6.5cm and ∠X = 75°
Construct an isosceles triangle in which: PQ = QR, PR = 4.5 cm and ∠R = 60°
Construct a triangle using the following data: XY + YZ = 5.6 cm, XZ = 4.5 cm and ∠X = 45°
Construct a triangle PQR with PQ = 5.4 cm, QR = 4.6 cm and ∠Q = 60°. Draw the perpendicular PS at QR, measure the lengths of SP and SQ,
Construct a ΔPQR with ∠Q = 60°, ∠R = 45° and the perpendicular from P to QR be 3.5 cm. Measure PQ.
Construct a ΔABC, right-angled at B with a perimeter of 10 cm and one acute angle of 60°.
