Advertisements
Advertisements
प्रश्न

In ∆PQR, the measures of ∠P and ∠Q are equal and m∠PRQ = 70°. Find the measures of the following angles.
- m∠PRT
- m∠P
- m∠Q
Advertisements
उत्तर
(i) ∠PRQ + ∠PRT = 180∘ ...(Linear pair angles)
⇒ 70° + ∠PRT = 180°
⇒ ∠PRT = 180∘ − 70°
= 110∘
Hence, the measure of ∠PRT is 110∘.
(ii) Now, ∠PRT is the exterior angle of ∆PQR.
∴ m∠P + m∠Q = m∠PRT ...(Exterior angle property)
∴ m∠P + m∠P = 110 ...(∠P = ∠Q)
∴ 2m∠P = 110
∴ m∠P = `110/2`
∴ m∠P = 55°
(iii) In ΔPQR
∴ m∠P + m∠Q = m∠PRT ...(Exterior angle property)
∴ m∠Q + m∠Q = 110 ...(∠P = ∠Q)
∴ 2m∠Q = 110
∴ m∠Q = `110/2`
∴ m∠Q = 55°
संबंधित प्रश्न
Find the value of the unknown exterior angle x in the following diagram:

Find the value of the unknown exterior angle x in the following diagram:

Find the value of the unknown interior angle x in the following figure.

Using the diagram find the value of x.
An exterior angle of a triangle is 70° and two interior opposite angles are equal. Then measure of each of these angle will be
If the exterior angle of a triangle is 140° and its interior opposite angles are equal, find all the interior angles of the triangle
Find the value of ‘x’ in the given figure
In the figure find the value of x
In the following figure, PQ = PR, RS = RQ and ST || QR. If the exterior angle RPU is 140°, then the measure of angle TSR is ______.

In ∆ABC, ∠Α = 50°, ∠B = 70° and bisector of ∠C meets AB in D (see figure). Measure of ∠ADC is ______.

