Advertisements
Advertisements
प्रश्न
In the following figure, BC = CA and ∠A = 40°. Then, ∠ACD is equal to ______.
पर्याय
40°
80°
120°
60°
Advertisements
उत्तर
In the following figure, BC = CA and ∠A = 40°. Then, ∠ACD is equal to 80°.
Explanation:
Given, BC = CA,
∴ ∠B = ∠A = 40° ...[∵ Opposite angles of two equal sides are equal]
As we know, the measure of any exterior angle of a triangle is equal to the sum of the measure of its two interior opposite angles.
So, ∠ACD = ∠A + ∠B = 40° + 40°
⇒ ∠ACD = 80°
APPEARS IN
संबंधित प्रश्न
∠ACD is an exterior angle of ∆ABC. The measures of ∠A and ∠B are equal. If m∠ACD = 140°, find the measures of the angles ∠A and ∠B.
In the isosceles triangle ABC, ∠A, and ∠B are equal. ∠ACD is an exterior angle of ∆ABC. The measures of ∠ACB and ∠ACD are (3x − 17)° and (8x + 10)°, respectively. Find the measures of ∠ACB and ∠ACD. Also find the measures of ∠A and ∠B.
Find the value of x in the given triangle
Find the value of x in the given triangle
In the given figure find the value of x
In the following figure, the value of ∠A + ∠B + ∠C + ∠D + ∠E + ∠F is ______.
If the exterior angle of a triangle is 130° and its interior opposite angles are equal, then measure of each interior opposite angle is ______.
In the following figure, if AB || CD, then ______.
In the following figure, if RP = RQ, find the value of x.
In the following figure, if y is five times x, find the value of z.
