Advertisements
Advertisements
प्रश्न
In the following figure, BC = CA and ∠A = 40°. Then, ∠ACD is equal to ______.
विकल्प
40°
80°
120°
60°
Advertisements
उत्तर
In the following figure, BC = CA and ∠A = 40°. Then, ∠ACD is equal to 80°.
Explanation:
Given, BC = CA,
∴ ∠B = ∠A = 40° ...[∵ Opposite angles of two equal sides are equal]
As we know, the measure of any exterior angle of a triangle is equal to the sum of the measure of its two interior opposite angles.
So, ∠ACD = ∠A + ∠B = 40° + 40°
⇒ ∠ACD = 80°
APPEARS IN
संबंधित प्रश्न
Find the value of the unknown exterior angle x in the following diagram:
Find the value of the unknown exterior angle x in the following diagram:
Find angle x in Fig
In the given figure BD = BC, find the value of x
In ∆ABC, ∠Α = 50°, ∠B = 70° and bisector of ∠C meets AB in D (see figure). Measure of ∠ADC is ______.
In the given figure, ∠UQR = ∠______ + ∠ ______
In the given figure, ∠PRS = ∠ ______ + ∠ _______
Find the measure of ∠A in the following figure.
In ∆ABC, if ∠A = ∠C, and exterior angle ABX = 140°, then find the angles of the triangle.
According to the Exterior Angle Rule, the measure of an exterior angle of a triangle is equal to the sum of which two angles?
