Advertisements
Advertisements
प्रश्न
Find the measure of ∠A in the following figure.
Advertisements
उत्तर
∠ACD = ∠ABC + ∠CAB ...[Exterior angle property]
⇒ 115° = 65° + ∠CAB
⇒ ∠CAB = 115° – 65° = 50°
Thus, ∠A = 50°
APPEARS IN
संबंधित प्रश्न
Find the value of the unknown interior angle x in the following figure.
Find the value of the unknown interior angle x in the following figure.
In the isosceles triangle ABC, ∠A, and ∠B are equal. ∠ACD is an exterior angle of ∆ABC. The measures of ∠ACB and ∠ACD are (3x − 17)° and (8x + 10)°, respectively. Find the measures of ∠ACB and ∠ACD. Also find the measures of ∠A and ∠B.
In ∆LMN, MN is extended to O. If ∠MLN = 100 – x, ∠LMN = 2x and ∠LNO = 6x – 5, find the value of x
Find the value of x in the given triangle
If the exterior angle of a triangle is 140° and its interior opposite angles are equal, find all the interior angles of the triangle
In the given figure find the values of x and y
In the figure find the value of x
According to the Exterior Angle Rule, the measure of an exterior angle of a triangle is equal to the sum of which two angles?
A triangle has interior opposite angles measuring 50° and 75°. What is the measure of the exterior angle at the third vertex?
