English Medium इयत्ता ९ - CBSE Question Bank Solutions

If a² + b² + c² − ab − bc − ca =0, then

If a + b + c = 0, then \[\frac{a^2}{bc} + \frac{b^2}{ca} + \frac{c^2}{ab} =\]

If a^1/3 + b^1/3 + c^1/3 = 0, then

If a + b + c = 9 and ab + bc + ca =23, then a³ + b³ + c³ − 3abc =

\[\frac{( a^2 - b^2 )^3 + ( b^2 - c^2 )^3 + ( c^2 - a^2 )^3}{(a - b )^3 + (b - c )^3 + (c - a )^3} =\]

The product (a + b) (a − b) (a² − ab + b²) (a² + ab + b²) is equal to

The product (x²−1) (x⁴ + x² + 1) is equal to

If \[\frac{a}{b} + \frac{b}{a} = 1\] then a³ + b³ =

If 49a² − b = \[\left( 7a + \frac{1}{2} \right) \left( 7a - \frac{1}{2} \right)\] then the value of b is 

Find:-

`32^(1/5)`

Find:-

`125^(1/3)`

Find:-

`32^(2/5)`

Find:-

`16^(3/4)`

Find:-

`125^((-1)/3)`

Simplify:-

`(1/3^3)^7`

Simplify:

`11^(1/2)/11^(1/4)`

Simplify:

`7^(1/2) . 8^(1/2)`

If O is the centre of the circle, find the value of x in the following figures.

If O is the centre of the circle, find the value of x in the following figures.

O is the circumcentre of the triangle ABC and OD is perpendicular on BC. Prove that ∠BOD = ∠A.