Advertisements
Advertisements
प्रश्न
The product (a + b) (a − b) (a2 − ab + b2) (a2 + ab + b2) is equal to
पर्याय
a6 + b6
a6 − b6
a3 − b3
a3 + b3
Advertisements
उत्तर
We have to find the product of `(a+b)(a-b)(a^2 - ab +b^2)(a^2+ab +b^2)`
Using identity
`a^3 +b^3 = (a+b)(a^2 - ab+b^2 )`
`a^3 -b^3 = (a-b)(a^2 +ab+b^2 )`
We can rearrange as
`= (a+b)(a^2 - ab +b^2)(a-b)(a^2 +ab+ b^2)`
`= (a^3 +b^3)(a^3 - b^3)`
Again using the identity `(a+b)(a-b)= a^2 -b^2`
Here `a = a^3,b = b^3`
`(a+b)(a-b) = a^2 - b^2`
` = (a^3)^2 - (b^3)^2`
` = a^6 - b^6`
Hence the product of `(a+b)(a^2 - ab +b^2)(a-b)(a^2+ab +b^2)` is `a^6 - b^6`.
APPEARS IN
संबंधित प्रश्न
Verify:
x3 + y3 = (x + y) (x2 – xy + y2)
Simplify (a + b + c)2 + (a - b + c)2 + (a + b - c)2
Simplify (2x + p - c)2 - (2x - p + c)2
Find the cube of the following binomials expression :
\[\frac{3}{x} - \frac{2}{x^2}\]
Evaluate the following:
(98)3
Simplify of the following:
(x+3)3 + (x−3)3
Find the following product:
\[\left( 3 + \frac{5}{x} \right) \left( 9 - \frac{15}{x} + \frac{25}{x^2} \right)\]
Find the following product:
(2ab − 3b − 2c) (4a2 + 9b2 +4c2 + 6 ab − 6 bc + 4ca)
If \[x - \frac{1}{x} = \frac{1}{2}\],then write the value of \[4 x^2 + \frac{4}{x^2}\]
Use identities to evaluate : (502)2
Evalute : `( 7/8x + 4/5y)^2`
If a - b = 0.9 and ab = 0.36; find:
(i) a + b
(ii) a2 - b2.
Find the squares of the following:
(2a + 3b - 4c)
Simplify by using formula :
(5x - 9) (5x + 9)
If `"a"^2 - 7"a" + 1` = 0 and a = ≠ 0, find :
`"a"^2 + (1)/"a"^2`
If a2 - 3a - 1 = 0 and a ≠ 0, find : `"a"^2 - (1)/"a"^2`
If a2 + b2 + c2 = 41 and a + b + c = 9; find ab + bc + ca.
Expand the following:
(3a – 5b – c)2
If a + b + c = 9 and ab + bc + ca = 26, find a2 + b2 + c2.
Find the value of x3 + y3 – 12xy + 64, when x + y = – 4
