Advertisements
Advertisements
प्रश्न
Find:-
`32^(2/5)`
बेरीज
Advertisements
उत्तर
We can write the given expression as follows
⇒ `32^(2/5) = (2^5)^(2/5)`
On simplifying
⇒ `32^(2/5) = 2^(5 xx 2/5)`
⇒ `32^(2/5) = 2^2`
∴ `32^(2/5) = 4`
shaalaa.com
या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
APPEARS IN
संबंधित प्रश्न
Simplify:-
`2^(2/3). 2^(1/5)`
Prove that:
`(x^a/x^b)^(a^2+ab+b^2)xx(x^b/x^c)^(b^2+bc+c^2)xx(x^c/x^a)^(c^2+ca+a^2)=1`
Solve the following equation for x:
`7^(2x+3)=1`
If \[8^{x + 1}\] = 64 , what is the value of \[3^{2x + 1}\] ?
If x is a positive real number and x2 = 2, then x3 =
If \[\frac{x}{x^{1 . 5}} = 8 x^{- 1}\] and x > 0, then x =
If \[x + \sqrt{15} = 4,\] then \[x + \frac{1}{x}\] =
If \[x = \frac{\sqrt{5} + \sqrt{3}}{\sqrt{5} - \sqrt{3}}\] and \[y = \frac{\sqrt{5} - \sqrt{3}}{\sqrt{5} + \sqrt{3}}\] then x + y +xy=
Simplify:-
`(1/3^3)^7`
Simplify:
`(3/5)^4 (8/5)^-12 (32/5)^6`
