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प्रश्न
Write IUPAC name of the following compound:
C6H5 – O – C2H5
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उत्तर
Ethoxybenzene
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संबंधित प्रश्न
Write structures of the compounds whose IUPAC names are as follows:
3-Chloromethylpentan-1-ol.
Give IUPAC name of the following ether:
Write IUPAC names of the following
One of the following is not a dihydroxy derivative of benzene.
Ethyl alcohol is industrially prepared from ethylene by:
HBr reacts fastest with ____________.
1-Propanol and 2-propanol can be best distinguished by:
Which of the following gives a positive iodoform test?
The correct acidic strength order of the following is:
(I)
(II)
(III)
IUPAC name of the compound \[\begin{array}{cc}
\ce{CH3 - CH - OCH3}\\
\phantom{}|\phantom{....}\\
\phantom{}\ce{CH3}\phantom{..}
\end{array}\] is ______.
Give IUPAC name of the compound given below.
\[\begin{array}{cc}
\phantom{}\ce{CH3 - CH - CH2 - CH2 - CH - CH3}\phantom{.}\\
\phantom{.........}|\phantom{...................}|\phantom{...........}\\
\phantom{..}\ce{Cl}\phantom{.................}\ce{OH}\phantom{..}
\end{array}\]
Match the starting materials given in Column I with the products formed by these (Column II) in the reaction with HI.
| Column I | Column II | ||
| (i) | CH3—O—CH3 | (a) |  |
| (ii) | \[\begin{array}{cc} \ce{CH3}\phantom{..................}\\ \backslash\phantom{.............}\\ \ce{CH-O-CH3}\\ /\phantom{..............}\\ \ce{CH3}\phantom{..................} \end{array}\] |
(b) | \[\begin{array}{cc} \ce{CH3}\phantom{....}\\ |\phantom{.......}\\ \ce{CH3-C-I + CH3OH}\\ |\phantom{.......}\\ \ce{CH3}\phantom{....} \end{array}\] |
| (iii) | \[\begin{array}{cc} \ce{CH3}\phantom{.}\\ |\phantom{....}\\ \ce{H3C-C-O-CH3}\\ |\phantom{....}\\ \ce{CH3}\phantom{..} \end{array}\] |
(c) |  |
| (iv) |  |
(d) | CH3—OH + CH3—I |
| (e) | \[\begin{array}{cc} \ce{CH3}\phantom{.....................}\\ \backslash\phantom{.................}\\ \ce{CH-OH + CH3I}\\ /\phantom{.................}\\ \ce{CH3}\phantom{.....................} \end{array}\] |
||
| (f) | \[\begin{array}{cc} \ce{CH3}\phantom{.....................}\\ \backslash\phantom{.................}\\ \ce{CH-I + CH3OH}\\ /\phantom{.................}\\ \ce{CH3}\phantom{.....................} \end{array}\] |
||
| (g) | \[\begin{array}{cc} \ce{CH3}\phantom{....}\\ |\phantom{.......}\\ \ce{CH3-C-OH + CH3I}\\ |\phantom{.......}\\ \ce{CH3}\phantom{....} \end{array}\] |
Assertion: Like bromination of benzene, bromination of phenol is also carried out in the presence of Lewis acid.
Reason: Lewis acid polarises the bromine molecule.
Assertion: Phenol forms 2, 4, 6 – tribromophenol on treatment with \[\ce{Br2}\] in carbon disulphide at 273 K.
Reason: Bromine polarises in carbon disulphide.
How can phenol be converted to aspirin?
Convert the following:
Ethyl alcohol into ethyl acetate.
Identify A and B in the following:
Draw structure of the following compound.
Prop-2-en-1-ol
The IUPAC name of 
is ______.
