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कर्नाटक बोर्ड पी.यू.सी.पीयूसी विज्ञान 2nd PUC Class 12

Use the formula λm T= 0.29 cm K to obtain the characteristic temperature ranges for different parts of the electromagnetic spectrum. What do the numbers that you obtain tell you?

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प्रश्न

Use the formula λm T= 0.29 cm K to obtain the characteristic temperature ranges for different parts of the electromagnetic spectrum. What do the numbers that you obtain tell you?

संख्यात्मक
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उत्तर

A body at a particular temperature produces a continuous spectrum of wavelengths. In the case of a black body, the wavelength corresponding to the maximum intensity of radiation is given according to Planck’s law. It can be given by the relation,

`lambda_"m" = 0.29/"T" "cm K"`

Where,

λm = maximum wavelength

T = temperature

Thus, the temperature for different wavelengths can be obtained as:

For λm = 10−4 cm; T = `0.29/10^-4` = 2900°K

For λm = 5 ×10−5 cm; T = `0.29/(5 xx 10^-5)` = 5800°K

For λm = 10−6 cm; T = `0.29/10^-6` = 290000°K and so on.

The numbers obtained tell us that temperature ranges are required for obtaining radiations in different parts of an electromagnetic spectrum. As the wavelength decreases, the corresponding temperature increases.

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पाठ 8: Electromagnetic Waves - Exercise [पृष्ठ २८७]

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एनसीईआरटी Physics Part I and II [English] Class 12
पाठ 8 Electromagnetic Waves
Exercise | Q 8.13 | पृष्ठ २८७

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