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प्रश्न
The temperatures of the junctions of a bismuth-silver thermocouple are maintained at 0°C and 0.001°C. Find the thermo-emf (Seebeck emf) developed. For bismuth-silver, a = − 46 × 10−6 V°C−1 and b = −0.48 × 10−6 V°C−2.
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उत्तर
Given:-
Difference in temperature, θ = 0.001°C,
a = − 46 × 10−6 V °C−1
b = − 0.48 × 10−5 V °C−2
Emf, E = aθ + \[\frac{1}{2}\]bθ2
⇒ E = (− 46 × 10−6) × (0.001)
\[- \frac{1}{2}\times\left(0.48\times10^{-6}\right)\times \left(0.001\right)^2\]
= − 46 × 10−9 − 0.24 × 10−12
= − 46.0024 × 10−9
= − 4.6 × 10−8 V
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