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प्रश्न
The power of a lens is + 0.2 D. Calculate its focal length.
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उत्तर
Power of a lens is given by:
Power (P) =`1/f`
`f=1/p`
`f=1/0.2=5m`
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संबंधित प्रश्न
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How unit of power related to focal length of a lens?
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(a) What is the power of this combination?
(b) What is the focal length of this combination?
(c) Is this combination converging or diverging?
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(2) an erect image of the tree on the lens.
(3) no image as the screen has been removed
(4) an inverted image of the tree at the focus of the lens.
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(iii) State three characteristics of the image.
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| Column - I | Column - II | ||
| 1 | Retina | a | Path way of light |
| 2 | Pupil | b | Far point comes closer |
| 3 | Ciliary muscles | c | near point moves away |
| 4 | Myopia | d | Screen of the eye |
| 5 | Hypermetropia | e | Power of accommodation |
Assertion and reasoning type
- Assertion: Myopia is due to the increase in the converging power of eye lens.
- Reason: Myopia can be corrected with the help of concave lens.
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