Advertisements
Advertisements
प्रश्न
Name the type of lens whose power is positive.
The image of an object formed by a lens is real, inverted and of the same size as the object. If the image is at a distance of 40 cm from the lens, what is the nature and power of the lens ? Draw ray diagram to justify your answer.
Advertisements
उत्तर
The power of a convex lens is positive.
It is given that the image of the object formed by the lens is real, inverted and of the same size as the object. Also, we know that only convex lens can form a real and inverted image. Thus, the given lens is a convex lens. In the given case, the object is placed at 2F1 and the image is formed at 2F2.
It is clear from the figure that the focal length of the lens (f) is 40 cm.
Now, power (P) is given by
\[P = \frac{1}{f}\]
\[\Rightarrow P = \frac{1}{20 \times {10}^{- 2} m}\]
\[ \Rightarrow P = + 5 D\]
APPEARS IN
संबंधित प्रश्न
Calculate the focal length of a corrective lens having power +2D.
A doctor has prescribed a corrective lens of power +1.5 D. Find the focal length of the lens. Is the prescribed lens diverging or converging?
How is the power of a lens related to its focal length?
A lens has a focal length of, −10 cm. What is the power of the lens and what is its nature?
The power of a lens is +2.0D. Its focal length should be :
A pin of length 2.00 cm is placed perpendicular to the principal axis of a converging lens. An inverted image of size 1.00 cm is formed at a distance of 40.0 cm from the pin. Find the focal length of the lens and its distance from the pin.
A stick partly immersed in water appears to be bent. Draw a ray diagram to show the bending of the stick when placed in water and viewed obliquely from above.
The power of lens depends on the focal length of the lens
An object is placed in front of a converging lens. Obtain the conditions under which the magnification produced by the lens is
- negative and
- positive.
