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प्रश्न

\[\int\frac{\sin \left( \text{log x} \right)}{x} dx\]
बेरीज
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उत्तर

\[\int\frac{\sin \left( \log x \right)}{x}dx\]
\[\text{Let }\log x = t\]
\[ \Rightarrow \frac{1}{x}dx = dt\]
\[Now, \int\frac{\sin \left( \log x \right)}{x}dx\]
\[ = \int\text{sin }\left( \text{t }\right) dt\]
\[ = - \text{cos} \left( \text{t }\right) + C\]
\[ = - \text{cos} \left( \text{log x} \right) + C\]

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पाठ 19: Indefinite Integrals - Exercise 19.09 [पृष्ठ ५९]

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आरडी शर्मा Mathematics [English] Class 12
पाठ 19 Indefinite Integrals
Exercise 19.09 | Q 53 | पृष्ठ ५९

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