English

∫ Sin ( Log X ) X D X - Mathematics

Advertisements
Advertisements

Question

\[\int\frac{\sin \left( \text{log x} \right)}{x} dx\]
Sum
Advertisements

Solution

\[\int\frac{\sin \left( \log x \right)}{x}dx\]
\[\text{Let }\log x = t\]
\[ \Rightarrow \frac{1}{x}dx = dt\]
\[Now, \int\frac{\sin \left( \log x \right)}{x}dx\]
\[ = \int\text{sin }\left( \text{t }\right) dt\]
\[ = - \text{cos} \left( \text{t }\right) + C\]
\[ = - \text{cos} \left( \text{log x} \right) + C\]

shaalaa.com
  Is there an error in this question or solution?
Chapter 19: Indefinite Integrals - Exercise 19.09 [Page 59]

APPEARS IN

RD Sharma Mathematics [English] Class 12
Chapter 19 Indefinite Integrals
Exercise 19.09 | Q 53 | Page 59

Video TutorialsVIEW ALL [1]

RELATED QUESTIONS

\[\int\left( 2 - 3x \right) \left( 3 + 2x \right) \left( 1 - 2x \right) dx\]

\[\int\left( x^e + e^x + e^e \right) dx\]

\[\int\frac{x^5 + x^{- 2} + 2}{x^2} dx\]

\[\int \left( e^x + 1 \right)^2 e^x dx\]

\[\int\frac{1}{\sqrt{x + 3} - \sqrt{x + 2}} dx\]

`  ∫  sin 4x cos  7x  dx  `

\[\int\frac{1}{\sqrt{1 - \cos 2x}} dx\]

\[\int\frac{a}{b + c e^x} dx\]

` ∫  tan 2x tan 3x  tan 5x    dx  `

\[\int\left( \frac{x + 1}{x} \right) \left( x + \log x \right)^2 dx\]

\[\int\frac{\sin \left( \tan^{- 1} x \right)}{1 + x^2} dx\]

\[\int\frac{\sec^2 \sqrt{x}}{\sqrt{x}} dx\]

` ∫  sec^6   x  tan    x   dx `

\[\int\frac{1}{\sqrt{3 x^2 + 5x + 7}} dx\]

\[\int\frac{1}{\sqrt{\left( x - \alpha \right)\left( \beta - x \right)}} dx, \left( \beta > \alpha \right)\]

\[\int\frac{1}{x^{2/3} \sqrt{x^{2/3} - 4}} dx\]

`  ∫ \sqrt{"cosec x"- 1}  dx `

\[\int\frac{2x - 3}{x^2 + 6x + 13} dx\]

\[\int\frac{1}{\cos 2x + 3 \sin^2 x} dx\]

\[\int\frac{1}{p + q \tan x} \text{ dx  }\]

\[\int\frac{4 \sin x + 5 \cos x}{5 \sin x + 4 \cos x} \text{ dx }\]

 
` ∫  x tan ^2 x dx 

\[\int \cos^{- 1} \left( \frac{1 - x^2}{1 + x^2} \right) \text{ dx }\]

\[\int \tan^{- 1} \left( \frac{2x}{1 - x^2} \right) \text{ dx }\]

\[\int\frac{\left( x \tan^{- 1} x \right)}{\left( 1 + x^2 \right)^{3/2}} \text{ dx }\]

\[\int x \sin x \cos 2x\ dx\]

\[\int \cos^3 \sqrt{x}\ dx\]

\[\int\frac{\sqrt{1 - \sin x}}{1 + \cos x} e^{- x/2}  \text{ dx }\]

\[\int\sqrt{2ax - x^2} \text{ dx}\]

\[\int\frac{x^2}{\left( x - 1 \right) \sqrt{x + 2}}\text{  dx}\]

\[\int\frac{x}{\left( x - 3 \right) \sqrt{x + 1}} \text{ dx}\]

\[\int\frac{\sin^6 x}{\cos^8 x} dx =\]

The primitive of the function \[f\left( x \right) = \left( 1 - \frac{1}{x^2} \right) a^{x + \frac{1}{x}} , a > 0\text{ is}\]


\[\int \sec^2 x \cos^2 2x \text{ dx }\]

\[\int\frac{1}{\text{ cos }\left( x - a \right) \text{ cos }\left( x - b \right)} \text{ dx }\]

\[\int\frac{1}{2 - 3 \cos 2x} \text{ dx }\]


\[\int\frac{\sin^6 x}{\cos x} \text{ dx }\]

\[\int\frac{1}{x \sqrt{1 + x^n}} \text{ dx}\]

Find :  \[\int\frac{e^x}{\left( 2 + e^x \right)\left( 4 + e^{2x} \right)}dx.\] 

 


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×