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∫ E M Tan − 1 X 1 + X 2 D X - Mathematics

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Question

\[\int\frac{e^{m \tan^{- 1} x}}{1 + x^2} dx\]
Sum
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Solution

\[\int\left( \frac{e^{m \tan^{- 1} x}}{1 + x^2} \right)dx\]
\[\text{Let} \tan^{- 1} x = t\]
\[ \Rightarrow \left( \frac{1}{1 + x^2} \right)dx = dt\]
\[Now, \int\left( \frac{e^{m \tan^{- 1} x}}{1 + x^2} \right)dx\]
\[ = \int e^{mt} dt\]
\[ = \frac{e^{mt}}{m} + C\]
\[ = \frac{e^{m \tan^{- 1} x}}{m} + C\]

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Chapter 19: Indefinite Integrals - Exercise 19.09 [Page 59]

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RD Sharma Mathematics [English] Class 12
Chapter 19 Indefinite Integrals
Exercise 19.09 | Q 54 | Page 59

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