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∫ 1 √ ( 1 − X 2 ) { 9 + ( Sin − 1 X ) 2 } D X - Mathematics

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Question

\[\int\frac{1}{\sqrt{\left( 1 - x^2 \right)\left\{ 9 + \left( \sin^{- 1} x \right)^2 \right\}}} dx\]
Sum
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Solution

\[\int\frac{dx}{\sqrt{\left( 1 - x^2 \right) \left( 9 + \left( \sin^{- 1} x \right)^2 \right)}}\]
\[\text{ let } \sin^{- 1} x = t\]
\[ \Rightarrow \frac{1}{\sqrt{1 - x^2}} dx = dt\]
\[Now, \int\frac{dx}{\sqrt{\left( 1 - x^2 \right) \left( 9 + \left( \sin^{- 1} x \right)^2 \right)}} \]
\[ = \int\frac{dt}{\sqrt{9 + t^2}}\]
\[ = \int\frac{dt}{\sqrt{3^2 + t^2}}\]
\[ = \text{ log } \left| t + \sqrt{3^2 + t^2} \right| + C\]
\[ = \text{ log }\left| \sin^{- 1} x + \sqrt{9 + \left( \sin^{- 1} x \right)^2} \right| + C\]

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Chapter 19: Indefinite Integrals - Exercise 19.18 [Page 99]

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RD Sharma Mathematics [English] Class 12
Chapter 19 Indefinite Integrals
Exercise 19.18 | Q 14 | Page 99

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