Question

\[\int \sin^5 x \cos x \text{ dx }\]

Answer 1

∫ sin⁵ x cos x dx
Let sin x = t
cos x dx = dt

Now, ∫ sin⁵ x cos x dx
​= ∫ t⁵ . dt

\[= \frac{t^6}{6} + C\]
\[ = \frac{\sin^6 x}{6} + C\]