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∫ Sin ( Tan − 1 X ) 1 + X 2 D X - Mathematics

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Question

\[\int\frac{\sin \left( \tan^{- 1} x \right)}{1 + x^2} dx\]
Sum
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Solution

\[\int\frac{\sin \left( \tan^{- 1} x \right)}{1 + x^2}dx\]
\[\text{Let} \tan^{- 1} x = t\]
\[ \Rightarrow \frac{1}{1 + x^2}dx = dt\]
\[Now, \int\frac{\sin \left( \tan^{- 1} x \right)}{1 + x^2}dx\]
\[ = \int\text{sin t dt} \]
\[ = - \cos \left( t \right) + C\]
\[ = - \cos \left( \tan^{- 1} x \right) + C\]

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Chapter 19: Indefinite Integrals - Exercise 19.09 [Page 59]

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RD Sharma Mathematics [English] Class 12
Chapter 19 Indefinite Integrals
Exercise 19.09 | Q 52 | Page 59

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