Advertisements
Advertisements
प्रश्न
\[\int\left( \sec^2 x + {cosec}^2 x \right) dx\]
बेरीज
Advertisements
उत्तर
\[\int\left( \sec^2 x + {cosec}^2 x \right)dx\]
\[ = \int \sec^2\text{ x dx} + \int {cosec}^2\text{ x dx}\]
\[ = \tan x - \cot x + C\]
shaalaa.com
या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
APPEARS IN
संबंधित प्रश्न
\[\int\left( x^e + e^x + e^e \right) dx\]
\[\int\frac{2x - 1}{\left( x - 1 \right)^2} dx\]
\[\int \sin^2\text{ b x dx}\]
` ∫ sin 4x cos 7x dx `
` = ∫ root (3){ cos^2 x} sin x dx `
\[\ \int\ x \left( 1 - x \right)^{23} dx\]
` ∫ tan x sec^4 x dx `
\[\int\frac{x}{\sqrt{x^4 + a^4}} dx\]
\[\int\frac{\cos x}{\sqrt{4 + \sin^2 x}} dx\]
\[\int\frac{\cos x}{\sqrt{4 - \sin^2 x}} dx\]
\[\int\frac{x + 7}{3 x^2 + 25x + 28}\text{ dx}\]
\[\int\frac{\left( 1 - x^2 \right)}{x \left( 1 - 2x \right)} \text
{dx\]
\[\int\frac{x^2}{x^2 + 7x + 10} dx\]
\[\int\frac{x^2 + x + 1}{x^2 - x + 1} \text{ dx }\]
\[\int\frac{6x - 5}{\sqrt{3 x^2 - 5x + 1}} \text{ dx }\]
\[\int\frac{1}{1 - \cot x} dx\]
\[\int x^2 \sin^{- 1} x\ dx\]
\[\int \cos^{- 1} \left( \frac{1 - x^2}{1 + x^2} \right) \text{ dx }\]
\[\int\frac{\left( x \tan^{- 1} x \right)}{\left( 1 + x^2 \right)^{3/2}} \text{ dx }\]
\[\int e^x \left( \tan x - \log \cos x \right) dx\]
\[\int e^x \left( \log x + \frac{1}{x^2} \right) dx\]
\[\int\frac{1}{x \log x \left( 2 + \log x \right)} dx\]
\[\int\frac{5}{\left( x^2 + 1 \right) \left( x + 2 \right)} dx\]
\[\int\frac{x^2}{\left( x^2 + 1 \right) \left( 3 x^2 + 4 \right)} dx\]
Evaluate the following integral:
\[\int\frac{x^2}{1 - x^4}dx\]
\[\int\frac{x + 1}{\left( x - 1 \right) \sqrt{x + 2}} \text{ dx }\]
\[\int\frac{e^x \left( 1 + x \right)}{\cos^2 \left( x e^x \right)} dx =\]
\[\int\frac{1}{e^x + e^{- x}} dx\]
\[\int\sin x \sin 2x \text{ sin 3x dx }\]
\[\int \sin^3 x \cos^4 x\ \text{ dx }\]
\[\int \cos^5 x\ dx\]
\[\int\frac{1}{x^2 + 4x - 5} \text{ dx }\]
\[\int\frac{\cos x}{\frac{1}{4} - \cos^2 x} \text{ dx }\]
\[\int\frac{1}{\sin^4 x + \cos^4 x} \text{ dx}\]
\[\int \sec^6 x\ dx\]
\[\int x\sqrt{1 + x - x^2}\text{ dx }\]
\[\int\frac{x^5}{\sqrt{1 + x^3}} \text{ dx }\]
\[\int\frac{x \sin^{- 1} x}{\left( 1 - x^2 \right)^{3/2}} \text{ dx}\]
