Advertisements
Advertisements
प्रश्न
Quadrilateral EFGH is a rectangle in which J is the point of intersection of the diagonals. Find the value of x if JF = 8x + 4 and EG = 24x – 8.
Advertisements
उत्तर
Given, EFGH is a rectangle in which diagonals are intersecting at the point J.
We know that, the diagonals of a rectangle bisect each other and are equal.
Then, EG = 2 × JF
⇒ 24x – 8 = 2(8x + 4)
⇒ 24x – 8 = 16x + 8
⇒ 24x – 16x = 8 + 8
⇒ 8x = 16
⇒ x = 2
APPEARS IN
संबंधित प्रश्न
Two adjacent angles of a parallelogram are (3x − 4)° and (3x + 10)°. Find the angles of the parallelogram.
The angle between the altitudes of a parallelogram, through the same vertex of an obtuse angle of the parallelogram is 60°. Find the angles of the parallelogram.

In Fig. 17.29, suppose it is known that DE = DF. Then, is ΔABC isosceles? Why or why not?
Find the length of the diagonal of a rectangle whose sides are 12 cm and 5 cm.
Draw a square whose each side measures 4.8 cm.
Prove that quadrilateral formed by the intersection of angle bisectors of all angles of a parallelogram is a rectangle.

State with Reason Whether the Following Statement is ‘True’ Or ‘False’.
Every rectangle is a parallelogram.
A parallelogram PQRS is constructed with sides QR = 6 cm, PQ = 4 cm and ∠PQR = 90°. Then PQRS is a ______.
In rectangle PAIR, find ∠ARI, ∠RMI and ∠PMA.

A rectangular MORE is shown below:

Answer the following questions by giving appropriate reason.
- Is RE = OM?
- Is ∠MYO = ∠RXE?
- Is ∠MOY = ∠REX?
- Is ΔMYO ≅ ΔRXE?
- Is MY = RX?
