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कर्नाटक बोर्ड पी.यू.सी.पीयूसी विज्ञान 2nd PUC Class 12

Preparation of ethers by acid dehydration of secondary or tertiary alcohols is not a suitable method. Give reason. - Chemistry

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प्रश्न

Preparation of ethers by acid dehydration of secondary or tertiary alcohols is not a suitable method. Give reason.

रासायनिक समीकरणे/रचना
कारण सांगा
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उत्तर

Acid dehydration of primary alcohols to ethers occurs by SN2 mechanism in which the nucleophilic attack of the alcohol molecule takes place on the protonated alcohol molecule.

\[\ce{CH3CH2CH2\overset{\bullet\bullet}{\underset{\bullet\bullet}{O}}H + CH3CH2CH2 - \overset{+}{\underset{\bullet\bullet}{O}}\overset{+}{H} ->[S_{N}2][-H^+, -H2O] CH3CH2CH2 - O - CH2CH2CH3}\]

Under these conditions, secondary and tertiary alcohols give alkenes instead of ethers. There is no nucleophilic attack of the alcohol molecule on the protonated alcohol molecule. Instead protonated secondary and tertiary alcohols lose a molecule of water to form stable 2° and 3° carbocations. These carbocations preferentially lose H+ to form alkenes.

\[\begin{array}{cc}
\phantom{.......}\ce{CH3}\phantom{.................}\ce{CH3}\phantom{....................}\ce{CH3}\phantom{.}\\\
\phantom{.....}|\phantom{.....................}|\phantom{........................}|\phantom{..}\\
\ce{\underset{\underset{(2^\circ alcohol)}{Propan-2-ol}}{CH3 - CH - OH} ->[H^-] \underset{Protonated 2^\circ alcohol}{CH3 - CH - \overset{+}{O}H2} ->[][-H2O] \underset{2^\circ Carbocation}{CH3 - CH^+}}
\end{array}\]

 

\[\begin{array}{cc}
\phantom{}\ce{CH3}\phantom{.......}\ce{CH3}\phantom{.........................}\ce{CH3}\phantom{..................}\\
\phantom{}|\phantom{..........}|\phantom{.............................}|\phantom{....................}\\
\ce{\underset{2-propoxy-2-propane}{CH3 - CH - O - CH - CH3} ->[CH3CHOCH3][-H^+] CH3 - CH^+ ->[][-H^+] \underset{Propene}{CH3 - CH = CH2}}
\end{array}\]

 

Similarly, 3° alcohols give alkenes instead of ethers.

\[\ce{\underset{\underset{(3^\circ alcohol)}{2-Methylpropan-2-ol}}{(CH3)3C - OH} ->[H^+] \underset{\underset{(3^\circ alcohol)}{Protonated 2-methylpropan-2-ol}}{(CH3)3C - \overset{+}{O}H2} ->[][-H2O] \underset{3^\circ butyl carbocation}{(CH3)3C^+}}\]

 

\[\begin{array}{cc}
\phantom{...}\ce{CH3}\phantom{.....}\ce{CH3}\phantom{.......................}\ce{CH3}\phantom{............}\ce{CH3}\phantom{...}\\
\phantom{.......}|\phantom{.........}|\phantom{..........................}|\phantom{................}|\phantom{.........}\\
\ce{CH3 - C - O - C - CH3 ->[(CH3)3COH][-H^+] CH3 - C^+ ->[][-H^+] \underset{2-Methylprop-1-ene}{CH3 - CH = CH2}}\\
\phantom{.....}|\phantom{.........}|\phantom{..........................}|\phantom{........................}\\
\phantom{}\ce{\underset{2-Methyl-2-(2-methyl-2-propoxy)propane}{\phantom{..}CH3\phantom{......}CH3}}\phantom{..........}\ce{\underset{3^\circ butyl carbocation}{CH3}}\phantom{....................}
\end{array}\]

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पाठ 7: Alcohols, Phenols and Ethers - Exercises [पृष्ठ २२४]

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एनसीईआरटी Chemistry Part 1 and 2 [English] Class 12
पाठ 7 Alcohols, Phenols and Ethers
Exercises | Q 7.27 | पृष्ठ २२४

संबंधित प्रश्‍न

Write the structure of 3-Bromo-2-methylprop-1-ene


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Williamson's synthesis of ether is an example of ______.


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2-Methoxy-2-methylpropane


Write the name of reagent and equation for the preparation of the following ethers by Williamson’s synthesis:

2-Methoxy-2-methylpropane


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Write the name of reagent and equation for the preparation of the following ethers by Williamson’s synthesis:

2-Methoxy-2-methylpropane


Short Answer Question.

Identify the product (s) is/are formed when 1 – methoxy propane is heated with excess HI. Name the mechanism involved in the reaction.


Write the name of reagent and equation for the preparation of the following ethers by Williamson’s synthesis:

2-Methoxy-2-methylpropane


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