The melting point of p-dichlorobenzene is higher than that of its ortho- and meta-isomers due to its highly symmetrical structure. This symmetry allows the molecules to pack more efficiently and tightly in the crystal lattice, forming a more stable and orderly solid. As a result, stronger intermolecular forces hold the molecules together, and more energy (heat) is required to break these interactions during melting. In contrast, the less symmetrical o- and m-isomers pack less efficiently, have weaker intermolecular forces, and thus melt at lower temperatures.
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प्रश्न
p-Dichlorobenzene has higher m.p. and lower solubility than those of o- and m-isomers. Discuss.
Why p-dichlorobenzene has higher melting point than those of ortho and meta-isomers?
p-Dichlorobenzene has higher m.p. than those of o- and m-isomers. Discuss.
Why is the melting point of p-dichlorobenzene higher than that of o- and m-isomers?
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संबंधित प्रश्न
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(a)

(b)

(c)

(d)

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(a) \[\begin{array}{cc}
\ce{CH3}\phantom{..................}\\
\backslash\phantom{...........}\\
\ce{CH - CH - CH2Br}\\
/\phantom{.............}\\
\ce{CH3}\phantom{..................}
\end{array}\]
(b) \[\ce{CH3CH2CH2CH2Br}\]
(c) \[\begin{array}{cc}
\phantom{...}\ce{CH3}\\
\phantom{}|\\
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\phantom{}|\\
\phantom{..}\ce{Br}
\end{array}\]
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