Advertisements
Advertisements
प्रश्न
One angle of a triangle is 60°. The other two angles are in the ratio of 5: 7. Find the two angles.
Advertisements
उत्तर
In Δ ABC,
Let ∠A = 60° and then ∠B: ∠C = 5: 7
But ∠A + ∠B + ∠C = 180° ........(Angles of a triangle)
⇒ 60° + ∠B + ∠C = 180°
⇒ ∠B + ∠C = 180°− 60° = 120°
Let ∠B = 5x and ∠C = 7x
∴ 5x + 7x = 120°
⇒ 12x = 120°
⇒ x =`(120°)/12=10°`
∴ ∠B = 5x = 5 × 10° = 50°
∠C = 7x = 7 × 10° = 70°
APPEARS IN
संबंधित प्रश्न
The bisectors of base angles of a triangle cannot enclose a right angle in any case.
Compute the value of x in the following figure:
Fill in the blank to make the following statement true:
An exterior angle of a triangle is always ......... than either of the interior opposite angles.
In Δ ABC, if u∠B = 60°, ∠C = 80° and the bisectors of angles ∠ABC and ∠ACB meet at a point O, then find the measure of ∠BOC.
Side BC of a triangle ABC has been produced to a point D such that ∠ACD = 120°. If ∠B = \[\frac{1}{2}\]∠A is equal to
Find the unknown marked angles in the given figure:
In the given figure, show that: ∠a = ∠b + ∠c
(i) If ∠b = 60° and ∠c = 50° ; find ∠a.
(ii) If ∠a = 100° and ∠b = 55° : find ∠c.
(iii) If ∠a = 108° and ∠c = 48° ; find ∠b.
The angles of a triangle are in the ratio 2 : 3 : 4. Then the angles are
AB and CD are the smallest and largest sides of a quadrilateral ABCD. Out of ∠B and ∠D decide which is greater.
In the following figure, AB = BC and AD = BD = DC. The number of isosceles triangles in the figure is ______.
