Advertisements
Advertisements
प्रश्न
Fill in the blank to make the following statement true:
An exterior angle of a triangle is always ......... than either of the interior opposite angles.
Advertisements
उत्तर
An exterior angle of a triangle is always greater than either of the interior opposite angles.
As according to the property: An exterior angle of a triangle is equal to the sum of two interior opposite angles. Therefore, it has to be greater than either of them.
APPEARS IN
संबंधित प्रश्न
If one angle of a triangle is equal to the sum of the other two, show that the triangle is a
right triangle.
Is the following statement true and false :
All the angles of a triangle can be greater than 60°.
An exterior angle of a triangle is equal to 100° and two interior opposite angles are equal. Each of these angles is equal to
In a triangle, an exterior angle at a vertex is 95° and its one of the interior opposite angle is 55°, then the measure of the other interior angle is
State, if the triangle is possible with the following angles :
125°, 40°, and 15°
Find, giving a reason, the unknown marked angles, in a triangle drawn below:
Match the following:
| Column A | Column B |
| (i) No sides are equal | Isosceles triangle |
| (ii) One right angle | Scalene triangle |
| (iii) One obtuse angle | Right angled triangle |
| (iv) Two sides of equal length | Equilateral triangle |
| (v) All sides are equal | Obtuse angled triangle |
D is any point on side AC of a ∆ABC with AB = AC. Show that CD < BD.
The image of an object placed at a point A before a plane mirror LM is seen at the point B by an observer at D as shown in the following figure. Prove that the image is as far behind the mirror as the object is in front of the mirror.
[Hint: CN is normal to the mirror. Also, angle of incidence = angle of reflection].
O is a point in the interior of a square ABCD such that OAB is an equilateral triangle. Show that ∆OCD is an isosceles triangle.
