Advertisements
Advertisements
प्रश्न
Find the unknown marked angles in the given figure:
Advertisements
उत्तर
In the figure,
∠A + ∠B + ∠C = 180° .....(Sum of angles of a triangle)
(m°− 5°) + 60° + (m°+ 5°) = 180°
⇒ m°− 5° + 60° + m° + 5° = 180°
⇒ 2m° = 180°− 65° + 5°
⇒ 2m° = 120°
⇒ ∴ m° = `(120°)/2=60°`
Hence ∠A = m°− 5° = 60°− 5° = 55°
and ∠C = m° + 5° = 60° + 5° = 65°
APPEARS IN
संबंधित प्रश्न
The angles of a triangle are (x − 40)°, (x − 20)° and `(1/2x-10)^@.` find the value of x
Can a triangle have All angles equal to 60°? Justify your answer in case.
If each angle of a triangle is less than the sum of the other two, show that the triangle is acute angled.
Is the following statement true and false :
A triangle can have two obtuse angles.
One angle of a triangle is 60°. The other two angles are in the ratio of 5: 7. Find the two angles.
In the following, find the marked unknown angle:
In the following, find the marked unknown angle:
Find, giving a reason, the unknown marked angles, in a triangle drawn below:
Match the following:
| Column A | Column B |
| (i) No sides are equal | Isosceles triangle |
| (ii) One right angle | Scalene triangle |
| (iii) One obtuse angle | Right angled triangle |
| (iv) Two sides of equal length | Equilateral triangle |
| (v) All sides are equal | Obtuse angled triangle |
Can we have two acute angles whose sum is an acute angle? Why or why not?
