Advertisements
Advertisements
प्रश्न
The bisectors of base angles of a triangle cannot enclose a right angle in any case.
Advertisements
उत्तर
In a ABC
Sum of all angles of triangles is `180^@`
i.e, `∠ A+∠ B+∠C =180^@` divide both sides by `2`
⇒ `1/2∠A+1/2∠B+1/2∠C=180^@`
⇒`1/2∠A+∠OBC+∠OBC=90^@` [∵ OB,OC insects ∠B and ∠C]
⇒`∠OBC+∠OCB=90^@-1/2A`
Now in `Δ OCB=180^@`
`∴ ∠ BOC+∠OBC+∠OCB=180^@`
⇒`∠ BOC+90^@-1/2∠A=180^@`
⇒ `∠ BOC=90^@-1/2 ∠A`
Hence, bisectors of a base angle cannot enclose right angle.
APPEARS IN
संबंधित प्रश्न
If one angle of a triangle is equal to the sum of the other two, show that the triangle is a
right triangle.
In the given figure, side BC of ΔABC is produced to point D such that bisectors of ∠ABC and ∠ACD meet at a point E. If ∠BAC = 68°, find ∠BEC.

If one angle of a triangle is equal to the sum of the other two angles, then the triangle is
An exterior angle of a triangle is 108° and its interior opposite angles are in the ratio 4 : 5. The angles of the triangle are
State, if the triangle is possible with the following angles :
125°, 40°, and 15°
The angle of a vertex of an isosceles triangle is 100°. Find its base angles.
Classify the following triangle according to angle:

In the given figure, AB is parallel to CD. Then the value of b is
Bisectors of the angles B and C of an isosceles triangle with AB = AC intersect each other at O. BO is produced to a point M. Prove that ∠MOC = ∠ABC.
Which two triangles have ∠B in common?
