Advertisements
Advertisements
प्रश्न
Calculate the angles of a triangle if they are in the ratio 4: 5: 6.
Advertisements
उत्तर
We know that sum of angles of a triangle is 180°
∴ ∠A + ∠B + ∠C = 180°
But ∠A: ∠B: ∠C = 4: 5: 6
Let ∠A = 4x, ∠B = 5x and ∠C = 6x,
then 4x + 5x + 6x = 180°
⇒ 15x = 180°
⇒ x = `(180°)/15=12°`
∴ ∠A = 4x = 4 × 12° = 48°
∠B = 5x = 5 × 12° = 60°
∠C = 6x = 6 × 12° = 72°
APPEARS IN
संबंधित प्रश्न
In a ΔABC, ∠ABC = ∠ACB and the bisectors of ∠ABC and ∠ACB intersect at O such that ∠BOC = 120°. Show that ∠A = ∠B = ∠C = 60°.
AB is a line segment. P and Q are points on opposite sides of AB such that each of them is equidistant from the points A and B (See Fig. 10.26). Show that the line PQ is perpendicular bisector of AB.
In the given figure, AB divides ∠DAC in the ratio 1 : 3 and AB = DB. Determine the value of x.
State, if the triangle is possible with the following angles :
20°, 70°, and 90°
In the following, find the marked unknown angle:
The length of the three segments is given for constructing a triangle. Say whether a triangle with these sides can be drawn. Give the reason for your answer.
17 cm, 7 cm, 8 cm
In the given figure, AB is parallel to CD. Then the value of b is
If an angle of a triangle is equal to the sum of the other two angles, find the type of the triangle
D is any point on side AC of a ∆ABC with AB = AC. Show that CD < BD.
Draw a rough sketch of a triangle ABC. Mark a point P in its interior and a point Q in its exterior. Is point A in its exterior or in its interior?
