Advertisements
Advertisements
प्रश्न
If an angle of a triangle is equal to the sum of the other two angles, find the type of the triangle
Advertisements
उत्तर
Let ∠B is the greater angle than by the given condition ∠B = ∠A + ∠C.
Sum of three angles of a triangle = 180°
∠A + ∠B + ∠C = 180°
∠A + (∠A + ∠C) + ∠C = 180°
2∠A + 2∠C = 180°
2(∠A + ∠C) = 180°
∠A + ∠C = `(180^circ)/2`
∠B = 90°
∴ One of the angle of the triangle = 90°
It will be a right angled triangle.
APPEARS IN
संबंधित प्रश्न
The angles of a triangle are (x − 40)°, (x − 20)° and `(1/2x-10)^@.` find the value of x
In a ΔABC, ∠ABC = ∠ACB and the bisectors of ∠ABC and ∠ACB intersect at O such that ∠BOC = 120°. Show that ∠A = ∠B = ∠C = 60°.
In a Δ ABC, the internal bisectors of ∠B and ∠C meet at P and the external bisectors of ∠B and ∠C meet at Q, Prove that ∠BPC + ∠BQC = 180°.
Find the unknown marked angles in the given figure:
Find the unknown marked angles in the given figure:
In the following, find the marked unknown angle:
The length of the three segments is given for constructing a triangle. Say whether a triangle with these sides can be drawn. Give the reason for your answer.
15 cm, 20 cm, 25 cm
Find all the three angles of the ΔABC
The number of angles in the following figure is ______.
What is the sum of the measures of the interior angles of any triangle, △ABC?
